What are the solutions to the equation x^2-2x-99=0 ?

The solutions to the equation x^2-2x-99=0 are x=11,x=-9

Find the zeros of x^2-2x-99=0

The zeros of x^2-2x-99=0 are x=11,x=-9

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x^{2} - 2 x - 99 = 0

x = 11, x = - 9

Solution steps

x^{2} - 2 x - 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 99 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 99) = 20

x_{1, 2} = \frac{- ( - 2 ) \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 20}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 20}{2 \cdot 1}

x = \frac{- ( - 2 ) + 20}{2 \cdot 1} : 11

x = \frac{- ( - 2 ) - 20}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 11, x = - 9

z^{2} - 2 z = 0

- 2 c = 72

19 \cdot 6

∣ x ∣ > 7

2 + 6 i

What are the solutions to the equation x^2-2x-99=0 ?
The solutions to the equation x^2-2x-99=0 are x=11,x=-9
Find the zeros of x^2-2x-99=0
The zeros of x^2-2x-99=0 are x=11,x=-9