What are the solutions to the equation 4-y^2=0 ?

The solutions to the equation 4-y^2=0 are y=2,y=-2

Find the zeros of 4-y^2=0

The zeros of 4-y^2=0 are y=2,y=-2

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4 - y^{2} = 0

y = 2, y = - 2

Solution steps

4 - y^{2} = 0

Move

4

to the right side

- y^{2} = - 4

Divide both sides by

- 1

y^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 4, y = - 4

4 = 2

- 4 = - 2

y = 2, y = - 2

3 x + 1 > 2 x - 5 > x - 7

- 9 - 3 n = - 3 (- 3 n - 5)

- m (2 + m) = 8

3 v + 3 = 9

3 x + 3 \geq x + 6

What are the solutions to the equation 4-y^2=0 ?
The solutions to the equation 4-y^2=0 are y=2,y=-2
Find the zeros of 4-y^2=0
The zeros of 4-y^2=0 are y=2,y=-2