What are the solutions to the equation -4x^2+16x=23 ?

The solutions to the equation -4x^2+16x=23 are x=2-i(sqrt(7))/2 ,x=2+i(sqrt(7))/2

Find the zeros of -4x^2+16x=23

The zeros of -4x^2+16x=23 are x=2-i(sqrt(7))/2 ,x=2+i(sqrt(7))/2

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- 4 x^{2} + 16 x = 23

x = 2 - i \frac{7}{2}, x = 2 + i \frac{7}{2}

Solution steps

- 4 x^{2} + 16 x = 23

Move

23

to the left side

- 4 x^{2} + 16 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 4 ) ( - 23 )}{2 ( - 4 )}

Simplify

1 6^{2} - 4 (- 4) (- 23) : 47 i

x_{1, 2} = \frac{- 16 \pm 4 7 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 16 + 4 7 i}{2 ( - 4 )}, x_{2} = \frac{- 16 - 4 7 i}{2 ( - 4 )}

x = \frac{- 16 + 4 7 i}{2 ( - 4 )} : 2 - i \frac{7}{2}

x = \frac{- 16 - 4 7 i}{2 ( - 4 )} : 2 + i \frac{7}{2}

The solutions to the quadratic equation are:

x = 2 - i \frac{7}{2}, x = 2 + i \frac{7}{2}

5 x^{2} - 11 x - 12 = 0

(x - 2)^{2} + 3 (x - 2) - 18 = 0

∣ - 7 + 2 ∣

- 1 - 1

1 < x < 3

What are the solutions to the equation -4x^2+16x=23 ?
The solutions to the equation -4x^2+16x=23 are x=2-i(sqrt(7))/2 ,x=2+i(sqrt(7))/2
Find the zeros of -4x^2+16x=23
The zeros of -4x^2+16x=23 are x=2-i(sqrt(7))/2 ,x=2+i(sqrt(7))/2