What is (2+i)/(-4-8i) ?

The solution to (2+i)/(-4-8i) is -1/5+3/20 i

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simplify (2+i)/(-4-8i)

simplify

\frac{2 + i}{- 4 - 8 i}

- \frac{1}{5} + \frac{3}{20} i

Solution steps

\frac{2 + i}{- 4 - 8 i}

Multiply by the conjugate

\frac{- 4 + 8 i}{- 4 + 8 i}

= \frac{( 2 + i ) ( - 4 + 8 i )}{( - 4 - 8 i ) ( - 4 + 8 i )}

Simplify

\frac{( 2 + i ) ( - 4 + 8 i )}{( - 4 - 8 i ) ( - 4 + 8 i )} : \frac{- 16 + 12 i}{80}

= \frac{- 16 + 12 i}{80}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{- 16}{80} + \frac{12}{80} i

Simplify

\frac{- 16}{80} + \frac{12}{80} i : - \frac{1}{5} + \frac{3}{20} i

= - \frac{1}{5} + \frac{3}{20} i

ln ∣ e ∣

3 x^{2} = 192

3 (6 + x) = 24

\frac{1}{1 + ( 0.1 ) ^{2}}

\frac{1}{2} (1)^{- \frac{1}{2}}