What is (3x)/(4x^2y)-(x+4y)/(5y^2) ?

The solution to (3x)/(4x^2y)-(x+4y)/(5y^2) is 3/(4xy)-(x+4y)/(5y^2)

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simplify (3x)/(4x^2y)-(x+4y)/(5y^2)

simplify

\frac{3 x}{4 x ^{2} y} - \frac{x + 4 y}{5 y ^{2}}

\frac{3}{4 x y} - \frac{x + 4 y}{5 y ^{2}}

Solution steps

\frac{3 x}{4 x ^{2} y} - \frac{x + 4 y}{5 y ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{x ^{1}}{x ^{2}} = \frac{1}{x ^{2 - 1}}

= \frac{3}{4 x ^{2 - 1} y} - \frac{x + 4 y}{5 y ^{2}}

Subtract the numbers:

2 - 1 = 1

= \frac{3}{4 x ^{1} y} - \frac{x + 4 y}{5 y ^{2}}

Apply exponent rule:

a^{1} = a

x^{1} = x

= \frac{3}{4 x y} - \frac{x + 4 y}{5 y ^{2}}

∣ x ∣ = \frac{7}{5}

- \frac{2}{9} - (- \frac{1}{5})

x^{2} + 2 x - 8 \geq 0

x - 9 = 8 (2 x + 3) - 18

- (2 x + 1) = 9 - 14 x

What is (3x)/(4x^2y)-(x+4y)/(5y^2) ?
The solution to (3x)/(4x^2y)-(x+4y)/(5y^2) is 3/(4xy)-(x+4y)/(5y^2)