What are the solutions to the equation 2x^2-4x-30=0 ?

The solutions to the equation 2x^2-4x-30=0 are x=5,x=-3

Find the zeros of 2x^2-4x-30=0

The zeros of 2x^2-4x-30=0 are x=5,x=-3

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2 x^{2} - 4 x - 30 = 0

x = 5, x = - 3

Solution steps

2 x^{2} - 4 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 30 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 30) = 16

x_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 16}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 16}{2 \cdot 2}

x = \frac{- ( - 4 ) + 16}{2 \cdot 2} : 5

x = \frac{- ( - 4 ) - 16}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

\frac{4 r ^{4} s ^{5}}{24 r ^{4} s ^{- 5}}

5 x^{2} - 33 x + 18

3 + 5^{2}

3 = - \frac{1}{4} (3) + b

\frac{12}{6 + 2}

What are the solutions to the equation 2x^2-4x-30=0 ?
The solutions to the equation 2x^2-4x-30=0 are x=5,x=-3
Find the zeros of 2x^2-4x-30=0
The zeros of 2x^2-4x-30=0 are x=5,x=-3