What are the solutions to the equation 2x^2-1=0 ?

The solutions to the equation 2x^2-1=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of 2x^2-1=0

The zeros of 2x^2-1=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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2 x^{2} - 1 = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Solution steps

2 x^{2} - 1 = 0

Move

1

to the right side

2 x^{2} = 1

Divide both sides by

2

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

- 2 (y + 2) + 7 = 3 (y + 6)

\frac{- 1 + ( - 1 ) ^{6} + 2 π ( - 1 ) ^{6}}{π ( 6 ) ^{2}}

4 r^{2} + 3 r - 7

\frac{2}{5} + \frac{3}{7} - \frac{1}{4}

4 \cdot 6 \div 2^{3}

What are the solutions to the equation 2x^2-1=0 ?
The solutions to the equation 2x^2-1=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of 2x^2-1=0
The zeros of 2x^2-1=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))