What are the solutions to the equation 3x^2+23x-8=0 ?

The solutions to the equation 3x^2+23x-8=0 are x= 1/3 ,x=-8

Find the zeros of 3x^2+23x-8=0

The zeros of 3x^2+23x-8=0 are x= 1/3 ,x=-8

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3 x^{2} + 23 x - 8 = 0

x = \frac{1}{3}, x = - 8

Solution steps

3 x^{2} + 23 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

2 3^{2} - 4 \cdot 3 (- 8) = 25

x_{1, 2} = \frac{- 23 \pm 25}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 23 + 25}{2 \cdot 3}, x_{2} = \frac{- 23 - 25}{2 \cdot 3}

x = \frac{- 23 + 25}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 23 - 25}{2 \cdot 3} : - 8

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 8

125 - 8 y^{3}

x^{3} + 6 x^{2} + 9 x + 2

1 + \frac{0.05}{4}

\frac{7}{\frac{6}{4}}

\frac{x ^{3} x ^{- 4} yy}{1}

What are the solutions to the equation 3x^2+23x-8=0 ?
The solutions to the equation 3x^2+23x-8=0 are x= 1/3 ,x=-8
Find the zeros of 3x^2+23x-8=0
The zeros of 3x^2+23x-8=0 are x= 1/3 ,x=-8