What is the answer to 2/3 [x-(1-(x-2)/3)]+1=x ?

The answer to 2/3 [x-(1-(x-2)/3)]+1=x is x=-1

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2/3 [x-(1-(x-2)/3)]+1=x

\frac{2}{3} [x - (1 - \frac{x - 2}{3})] + 1 = x

x = - 1

Solution steps

\frac{2}{3} [x - (1 - \frac{x - 2}{3})] + 1 = x

Multiply

\frac{2}{3} (x - (1 - \frac{x - 2}{3})) : \frac{2 ( x - ( - \frac{x - 2}{3} + 1 ) )}{3}

\frac{2 ( x - ( 1 - \frac{x - 2}{3} ) )}{3} + 1 = x

Move

1

to the right side

\frac{2 ( x - ( 1 - \frac{x - 2}{3} ) )}{3} = x - 1

Expand

\frac{2 ( x - ( 1 - \frac{x - 2}{3} ) )}{3} : \frac{8 x}{9} - \frac{10}{9}

\frac{8 x}{9} - \frac{10}{9} = x - 1

Multiply both sides by

9

8 x - 10 = 9 x - 9

Move

10

to the right side

8 x = 9 x + 1

Move

9 x

to the left side

- x = 1

Divide both sides by

- 1

x = - 1

x^{2} \geq 121

81 x^{2} - 36 x + 4

8 y - 36

w^{2} - 14 w + 49

342

What is the answer to 2/3 [x-(1-(x-2)/3)]+1=x ?
The answer to 2/3 [x-(1-(x-2)/3)]+1=x is x=-1
Solve for x: 2/3 [x-(1-(x-2)/3)]+1=x
The solution is x=-1