What are the solutions to the equation 2x^2=9 ?

The solutions to the equation 2x^2=9 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

Find the zeros of 2x^2=9

The zeros of 2x^2=9 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

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2 x^{2} = 9

x = \frac{3}{2}, x = - \frac{3}{2}

Solution steps

2 x^{2} = 9

Divide both sides by

2

x^{2} = \frac{9}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{2}, x = - \frac{9}{2}

\frac{9}{2} = \frac{3}{2}

- \frac{9}{2} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

6 n^{4} - 6

15 \leq - 6 x

5 - 3 [2 - 4 (x - 2)] \geq 6 {2 - [4 - (x - 3)]}

36 x^{2} + 25 = 60 x

x^{2} - 25 x

What are the solutions to the equation 2x^2=9 ?
The solutions to the equation 2x^2=9 are x= 3/(sqrt(2)),x=-3/(sqrt(2))
Find the zeros of 2x^2=9
The zeros of 2x^2=9 are x= 3/(sqrt(2)),x=-3/(sqrt(2))