What are the solutions to the equation x^2-11x+13=0 ?

The solutions to the equation x^2-11x+13=0 are x=(11+sqrt(69))/2 ,x=(11-sqrt(69))/2

Find the zeros of x^2-11x+13=0

The zeros of x^2-11x+13=0 are x=(11+sqrt(69))/2 ,x=(11-sqrt(69))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 11 x + 13 = 0

x = \frac{11 + 69}{2}, x = \frac{11 - 69}{2}

Solution steps

x^{2} - 11 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 13 = 69

x_{1, 2} = \frac{- ( - 11 ) \pm 69}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 69}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 69}{2 \cdot 1}

x = \frac{- ( - 11 ) + 69}{2 \cdot 1} : \frac{11 + 69}{2}

x = \frac{- ( - 11 ) - 69}{2 \cdot 1} : \frac{11 - 69}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 69}{2}, x = \frac{11 - 69}{2}

3 a - 7 (3 - a) = 5

r^{4} - 4096

- 35 = - 5 (4 + x)

5 x^{2} - 8 x + 19 > 0

3 ∣ 5 x ∣ + 4 = 16

What are the solutions to the equation x^2-11x+13=0 ?
The solutions to the equation x^2-11x+13=0 are x=(11+sqrt(69))/2 ,x=(11-sqrt(69))/2
Find the zeros of x^2-11x+13=0
The zeros of x^2-11x+13=0 are x=(11+sqrt(69))/2 ,x=(11-sqrt(69))/2