What are the solutions to the equation x^2+4-6=2x ?

The solutions to the equation x^2+4-6=2x are x=1+sqrt(3),x=1-sqrt(3)

Find the zeros of x^2+4-6=2x

The zeros of x^2+4-6=2x are x=1+sqrt(3),x=1-sqrt(3)

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x^{2} + 4 - 6 = 2 x

x = 1 + 3, x = 1 - 3

Solution steps

x^{2} + 4 - 6 = 2 x

Refine

x^{2} - 2 = 2 x

Move

2 x

to the left side

x^{2} - 2 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 2) = 23

x_{1, 2} = \frac{- ( - 2 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 3}{2 \cdot 1} : 1 + 3

x = \frac{- ( - 2 ) - 2 3}{2 \cdot 1} : 1 - 3

The solutions to the quadratic equation are:

x = 1 + 3, x = 1 - 3

54 - 24

4 - 3 ∣ 4 - x ∣ = 2 ∣ 4 - x ∣ - 1

- 6 y - 3 = 3 - 6 y

25 m^{2} - 60 m + 36

(7 + 5) (7 - 5)

What are the solutions to the equation x^2+4-6=2x ?
The solutions to the equation x^2+4-6=2x are x=1+sqrt(3),x=1-sqrt(3)
Find the zeros of x^2+4-6=2x
The zeros of x^2+4-6=2x are x=1+sqrt(3),x=1-sqrt(3)