What is the answer to (c^4-c^2+1)(c^4+c^2+1)=c^8+c^4+1 ?

The answer to (c^4-c^2+1)(c^4+c^2+1)=c^8+c^4+1 is True for all c

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(c^4-c^2+1)(c^4+c^2+1)=c^8+c^4+1

(c^{4} - c^{2} + 1) (c^{4} + c^{2} + 1) = c^{8} + c^{4} + 1

True for all c

Solution steps

(c^{4} - c^{2} + 1) (c^{4} + c^{2} + 1) = c^{8} + c^{4} + 1

Expand

(c^{4} - c^{2} + 1) (c^{4} + c^{2} + 1) : c^{8} + c^{4} + 1

c^{8} + c^{4} + 1 = c^{8} + c^{4} + 1

Move

1

to the right side

c^{8} + c^{4} = c^{8} + c^{4}

Subtract

c^{8} + c^{4}

from both sides

c^{8} + c^{4} - (c^{8} + c^{4}) = c^{8} + c^{4} - (c^{8} + c^{4})

Simplify

0 = 0

Both sides are equal

True for all c

18 h^{2} + 15 h - 18

\frac{1 + i}{i}

x^{4}

\frac{x}{2} \geq 59

\frac{5 z - 3}{3} + \frac{11}{6} = \frac{10 z + 1}{6}

What is the answer to (c^4-c^2+1)(c^4+c^2+1)=c^8+c^4+1 ?
The answer to (c^4-c^2+1)(c^4+c^2+1)=c^8+c^4+1 is True for all c
Solve for c: (c^4-c^2+1)(c^4+c^2+1)=c^8+c^4+1
The solution is True for all c