What are the solutions to the equation -3x^2+4x-0.25=0 ?

The solutions to the equation -3x^2+4x-0.25=0 are x=(4-sqrt(13))/6 ,x=(4+sqrt(13))/6

Find the zeros of -3x^2+4x-0.25=0

The zeros of -3x^2+4x-0.25=0 are x=(4-sqrt(13))/6 ,x=(4+sqrt(13))/6

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- 3 x^{2} + 4 x - 0.25 = 0

x = \frac{4 - 13}{6}, x = \frac{4 + 13}{6}

Solution steps

- 3 x^{2} + 4 x - 0.25 = 0

Multiply both sides by

100

- 300 x^{2} + 400 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 ( - 300 ) ( - 25 )}{2 ( - 300 )}

40 0^{2} - 4 (- 300) (- 25) = 10013

x_{1, 2} = \frac{- 400 \pm 100 13}{2 ( - 300 )}

Separate the solutions

x_{1} = \frac{- 400 + 100 13}{2 ( - 300 )}, x_{2} = \frac{- 400 - 100 13}{2 ( - 300 )}

x = \frac{- 400 + 100 13}{2 ( - 300 )} : \frac{4 - 13}{6}

x = \frac{- 400 - 100 13}{2 ( - 300 )} : \frac{4 + 13}{6}

The solutions to the quadratic equation are:

x = \frac{4 - 13}{6}, x = \frac{4 + 13}{6}

12 = x (240)^{2}

20 a - 21 = 18

e^{0.69314}

\frac{1}{2} + \frac{3}{2} - \frac{3}{2}

\frac{74}{8} = 9 R^{2}

What are the solutions to the equation -3x^2+4x-0.25=0 ?
The solutions to the equation -3x^2+4x-0.25=0 are x=(4-sqrt(13))/6 ,x=(4+sqrt(13))/6
Find the zeros of -3x^2+4x-0.25=0
The zeros of -3x^2+4x-0.25=0 are x=(4-sqrt(13))/6 ,x=(4+sqrt(13))/6