What are the solutions to the equation k^2-13k+40=0 ?

The solutions to the equation k^2-13k+40=0 are k=8,k=5

Find the zeros of k^2-13k+40=0

The zeros of k^2-13k+40=0 are k=8,k=5

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k^{2} - 13 k + 40 = 0

k = 8, k = 5

Solution steps

k^{2} - 13 k + 40 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 40 = 3

k_{1, 2} = \frac{- ( - 13 ) \pm 3}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 13 ) + 3}{2 \cdot 1}, k_{2} = \frac{- ( - 13 ) - 3}{2 \cdot 1}

k = \frac{- ( - 13 ) + 3}{2 \cdot 1} : 8

k = \frac{- ( - 13 ) - 3}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

k = 8, k = 5

\frac{x - 2}{x + 3} > 1

- 5 < x < 5

(3 x^{2}) (4 x^{4})

24 a^{2} - 30 a + 9

2 x - 3 = 4 - 2 x

What are the solutions to the equation k^2-13k+40=0 ?
The solutions to the equation k^2-13k+40=0 are k=8,k=5
Find the zeros of k^2-13k+40=0
The zeros of k^2-13k+40=0 are k=8,k=5