What are the solutions to the equation (x+4)(x-15)=6x ?

The solutions to the equation (x+4)(x-15)=6x are x=20,x=-3

Find the zeros of (x+4)(x-15)=6x

The zeros of (x+4)(x-15)=6x are x=20,x=-3

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(x + 4) (x - 15) = 6 x

x = 20, x = - 3

Solution steps

(x + 4) (x - 15) = 6 x

Expand

(x + 4) (x - 15) : x^{2} - 11 x - 60

x^{2} - 11 x - 60 = 6 x

Move

6 x

to the left side

x^{2} - 17 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot (- 60) = 23

x_{1, 2} = \frac{- ( - 17 ) \pm 23}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 23}{2 \cdot 1}, x_{2} = \frac{- ( - 17 ) - 23}{2 \cdot 1}

x = \frac{- ( - 17 ) + 23}{2 \cdot 1} : 20

x = \frac{- ( - 17 ) - 23}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 20, x = - 3

3 x^{3} - 18 x^{2} + 15 x

49 x^{8} y z^{4} + 28 x^{4} y^{4} z^{3}

x + 3 = x^{2} + 5 x + 6

x^{2} y^{2} - 9 y^{2} - 4 x^{2} + 36

b^{2} + 2 b = - 20

What are the solutions to the equation (x+4)(x-15)=6x ?
The solutions to the equation (x+4)(x-15)=6x are x=20,x=-3
Find the zeros of (x+4)(x-15)=6x
The zeros of (x+4)(x-15)=6x are x=20,x=-3