What are the solutions to the equation 3(x+2)^2=48 ?

The solutions to the equation 3(x+2)^2=48 are x=2,x=-6

Find the zeros of 3(x+2)^2=48

The zeros of 3(x+2)^2=48 are x=2,x=-6

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3 (x + 2)^{2} = 48

x = 2, x = - 6

Solution steps

3 (x + 2)^{2} = 48

Divide both sides by

3

(x + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 16 : x = 2

Solve

x + 2 = - 16 : x = - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

- 3 (3 h - 1) \leq - 7 h - 5

(\frac{3 x ^{- 1}}{4 y ^{- 1}})^{- 2}

- 5 \leq 2 x + 7 < 9

3 x + 28 \leq 25

2 (4 w - 6) = 36

What are the solutions to the equation 3(x+2)^2=48 ?
The solutions to the equation 3(x+2)^2=48 are x=2,x=-6
Find the zeros of 3(x+2)^2=48
The zeros of 3(x+2)^2=48 are x=2,x=-6