What are the solutions to the equation 10x^2+x=2 ?

The solutions to the equation 10x^2+x=2 are x= 2/5 ,x=-1/2

Find the zeros of 10x^2+x=2

The zeros of 10x^2+x=2 are x= 2/5 ,x=-1/2

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10 x^{2} + x = 2

x = \frac{2}{5}, x = - \frac{1}{2}

Solution steps

10 x^{2} + x = 2

Move

2

to the left side

10 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 10 ( - 2 )}{2 \cdot 10}

1^{2} - 4 \cdot 10 (- 2) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 10}, x_{2} = \frac{- 1 - 9}{2 \cdot 10}

x = \frac{- 1 + 9}{2 \cdot 10} : \frac{2}{5}

x = \frac{- 1 - 9}{2 \cdot 10} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - \frac{1}{2}

\frac{4}{8} = \frac{x}{10}

- 6 < 4 - 2 x \leq - 1

∣ 4 x + 8 ∣ - 19 = - 6

33 \cdot 2

12 = x 3

What are the solutions to the equation 10x^2+x=2 ?
The solutions to the equation 10x^2+x=2 are x= 2/5 ,x=-1/2
Find the zeros of 10x^2+x=2
The zeros of 10x^2+x=2 are x= 2/5 ,x=-1/2