What are the solutions to the equation 3x^2-14x+16=0 ?

The solutions to the equation 3x^2-14x+16=0 are x= 8/3 ,x=2

Find the zeros of 3x^2-14x+16=0

The zeros of 3x^2-14x+16=0 are x= 8/3 ,x=2

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3 x^{2} - 14 x + 16 = 0

x = \frac{8}{3}, x = 2

Solution steps

3 x^{2} - 14 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 3 \cdot 16}{2 \cdot 3}

(- 14)^{2} - 4 \cdot 3 \cdot 16 = 2

x_{1, 2} = \frac{- ( - 14 ) \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2}{2 \cdot 3}, x_{2} = \frac{- ( - 14 ) - 2}{2 \cdot 3}

x = \frac{- ( - 14 ) + 2}{2 \cdot 3} : \frac{8}{3}

x = \frac{- ( - 14 ) - 2}{2 \cdot 3} : 2

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = 2

x + i y + \frac{1}{x + i y}

2 + 2 s > 8

\frac{3 a ^{- 1} + 2 b ^{- 2}}{a ^{- 1} - b ^{- 1}}

- 6 q + 1 \geq 2 q - 10

3 m^{2} \leq 9 m

What are the solutions to the equation 3x^2-14x+16=0 ?
The solutions to the equation 3x^2-14x+16=0 are x= 8/3 ,x=2
Find the zeros of 3x^2-14x+16=0
The zeros of 3x^2-14x+16=0 are x= 8/3 ,x=2