What are the solutions to the equation 5(3x-10)(x-10)=1435 ?

The solutions to the equation 5(3x-10)(x-10)=1435 are x=17,x=-11/3

Find the zeros of 5(3x-10)(x-10)=1435

The zeros of 5(3x-10)(x-10)=1435 are x=17,x=-11/3

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5 (3 x - 10) (x - 10) = 1435

x = 17, x = - \frac{11}{3}

Solution steps

5 (3 x - 10) (x - 10) = 1435

Expand

5 (3 x - 10) (x - 10) : 15 x^{2} - 200 x + 500

15 x^{2} - 200 x + 500 = 1435

Move

1435

to the left side

15 x^{2} - 200 x - 935 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 15 ( - 935 )}{2 \cdot 15}

(- 200)^{2} - 4 \cdot 15 (- 935) = 310

x_{1, 2} = \frac{- ( - 200 ) \pm 310}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 310}{2 \cdot 15}, x_{2} = \frac{- ( - 200 ) - 310}{2 \cdot 15}

x = \frac{- ( - 200 ) + 310}{2 \cdot 15} : 17

x = \frac{- ( - 200 ) - 310}{2 \cdot 15} : - \frac{11}{3}

The solutions to the quadratic equation are:

x = 17, x = - \frac{11}{3}

45 + 25

\frac{x}{- 4} \geq - 1

\frac{x}{4} = \frac{3}{2}

10 x y + 5 x - 4 y - 2

What are the solutions to the equation 5(3x-10)(x-10)=1435 ?
The solutions to the equation 5(3x-10)(x-10)=1435 are x=17,x=-11/3
Find the zeros of 5(3x-10)(x-10)=1435
The zeros of 5(3x-10)(x-10)=1435 are x=17,x=-11/3