What are the solutions to the equation 8x^2-3=0 ?

The solutions to the equation 8x^2-3=0 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))

Find the zeros of 8x^2-3=0

The zeros of 8x^2-3=0 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))

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8 x^{2} - 3 = 0

x = \frac{3}{2 2}, x = - \frac{3}{2 2}

Solution steps

8 x^{2} - 3 = 0

Move

3

to the right side

8 x^{2} = 3

Divide both sides by

8

x^{2} = \frac{3}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{8}, x = - \frac{3}{8}

\frac{3}{8} = \frac{3}{2 2}

- \frac{3}{8} = - \frac{3}{2 2}

x = \frac{3}{2 2}, x = - \frac{3}{2 2}

108 = - 16 x^{2} - 22 + 220

2 a a^{2}

∣ 1 - 6 x ∣ - 11 < - 8

x (x - 2) < 0

\frac{∣ 7 - 6 x ∣}{∣ 6 x - 2 ∣} \geq 1

What are the solutions to the equation 8x^2-3=0 ?
The solutions to the equation 8x^2-3=0 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))
Find the zeros of 8x^2-3=0
The zeros of 8x^2-3=0 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))