What are the solutions to the equation 5y^2+9y=-4 ?

The solutions to the equation 5y^2+9y=-4 are y=-4/5 ,y=-1

Find the zeros of 5y^2+9y=-4

The zeros of 5y^2+9y=-4 are y=-4/5 ,y=-1

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5 y^{2} + 9 y = - 4

y = - \frac{4}{5}, y = - 1

Solution steps

5 y^{2} + 9 y = - 4

Move

4

to the left side

5 y^{2} + 9 y + 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

9^{2} - 4 \cdot 5 \cdot 4 = 1

y_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 9 + 1}{2 \cdot 5}, y_{2} = \frac{- 9 - 1}{2 \cdot 5}

y = \frac{- 9 + 1}{2 \cdot 5} : - \frac{4}{5}

y = \frac{- 9 - 1}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

y = - \frac{4}{5}, y = - 1

- \frac{5}{- 2}

- 9 m - 9 = 9

S = 180 (6 - 2)

2 (- 27)^{\frac{10}{3}}

2 (\frac{1}{3})^{3}

What are the solutions to the equation 5y^2+9y=-4 ?
The solutions to the equation 5y^2+9y=-4 are y=-4/5 ,y=-1
Find the zeros of 5y^2+9y=-4
The zeros of 5y^2+9y=-4 are y=-4/5 ,y=-1