What are the solutions to the equation -3x^2+6x-5=0 ?

The solutions to the equation -3x^2+6x-5=0 are x=1-isqrt(2/3),x=1+isqrt(2/3)

Find the zeros of -3x^2+6x-5=0

The zeros of -3x^2+6x-5=0 are x=1-isqrt(2/3),x=1+isqrt(2/3)

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- 3 x^{2} + 6 x - 5 = 0

x = 1 - i \frac{2}{3}, x = 1 + i \frac{2}{3}

Solution steps

- 3 x^{2} + 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) ( - 5 )}{2 ( - 3 )}

Simplify

6^{2} - 4 (- 3) (- 5) : 26 i

x_{1, 2} = \frac{- 6 \pm 2 6 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 6 i}{2 ( - 3 )}, x_{2} = \frac{- 6 - 2 6 i}{2 ( - 3 )}

x = \frac{- 6 + 2 6 i}{2 ( - 3 )} : 1 - i \frac{2}{3}

x = \frac{- 6 - 2 6 i}{2 ( - 3 )} : 1 + i \frac{2}{3}

The solutions to the quadratic equation are:

x = 1 - i \frac{2}{3}, x = 1 + i \frac{2}{3}

y (y - 10) + 30 = 0

x + 2 < 9 x + 6

\frac{6}{x - 4} \leq \frac{3}{x - 3}

2 (12 - w) = - 2 (w - 17) - 10

\frac{b}{9} - 34 < - 36

What are the solutions to the equation -3x^2+6x-5=0 ?
The solutions to the equation -3x^2+6x-5=0 are x=1-isqrt(2/3),x=1+isqrt(2/3)
Find the zeros of -3x^2+6x-5=0
The zeros of -3x^2+6x-5=0 are x=1-isqrt(2/3),x=1+isqrt(2/3)