What are the solutions to the equation 12m^2+11m=15 ?

The solutions to the equation 12m^2+11m=15 are m= 3/4 ,m=-5/3

Find the zeros of 12m^2+11m=15

The zeros of 12m^2+11m=15 are m= 3/4 ,m=-5/3

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12 m^{2} + 11 m = 15

m = \frac{3}{4}, m = - \frac{5}{3}

Solution steps

12 m^{2} + 11 m = 15

Move

15

to the left side

12 m^{2} + 11 m - 15 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 12 ( - 15 )}{2 \cdot 12}

1 1^{2} - 4 \cdot 12 (- 15) = 29

m_{1, 2} = \frac{- 11 \pm 29}{2 \cdot 12}

Separate the solutions

m_{1} = \frac{- 11 + 29}{2 \cdot 12}, m_{2} = \frac{- 11 - 29}{2 \cdot 12}

m = \frac{- 11 + 29}{2 \cdot 12} : \frac{3}{4}

m = \frac{- 11 - 29}{2 \cdot 12} : - \frac{5}{3}

The solutions to the quadratic equation are:

m = \frac{3}{4}, m = - \frac{5}{3}

4 - 2 x + 6 = 10 - 9 x + 7

(s^{2} + 6 s + 8) (2 s - 4) - (s^{2} - 4 s + 20) (2 s + 6) = 0

- 3 \frac{w}{2} + 4 - 1 = - 4

\frac{1}{\frac{1}{4}}

5 x^{2} = 7 x + 6

What are the solutions to the equation 12m^2+11m=15 ?
The solutions to the equation 12m^2+11m=15 are m= 3/4 ,m=-5/3
Find the zeros of 12m^2+11m=15
The zeros of 12m^2+11m=15 are m= 3/4 ,m=-5/3