What is factor 20x^2-x-1 ?

The solution to factor 20x^2-x-1 is (5x+1)(4x-1)

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factor 20x^2-x-1

factor

20 x^{2} - x - 1

(5 x + 1) (4 x - 1)

Solution steps

20 x^{2} - x - 1

Break the expression into groups

= (20 x^{2} + 4 x) + (- 5 x - 1)

Factor out

4 x

from

20 x^{2} + 4 x : 4 x (5 x + 1)

Factor out

- 1

from

- 5 x - 1 : - (5 x + 1)

= 4 x (5 x + 1) - (5 x + 1)

Factor out common term

(5 x + 1) : (5 x + 1) (4 x - 1)

= (5 x + 1) (4 x - 1)

36 \cdot 6

270 \cdot \frac{π}{180}

\frac{1}{2} \frac{1}{3}

(3)^{4} \cdot (3)^{3}

(\frac{1}{3})^{- 5}