What are the solutions to the equation y^2-10y+24=0 ?

The solutions to the equation y^2-10y+24=0 are y=6,y=4

Find the zeros of y^2-10y+24=0

The zeros of y^2-10y+24=0 are y=6,y=4

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y^{2} - 10 y + 24 = 0

y = 6, y = 4

Solution steps

y^{2} - 10 y + 24 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

y_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, y_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

y = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

y = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

y = 6, y = 4

(\frac{x ^{5}}{x ^{4}})^{- 2}

\frac{7}{4} + \frac{7}{4}

3 x = 0.5 x^{2}

3 g + 1 \leq 7

5 (x + 4) = 7 (x - 2)

What are the solutions to the equation y^2-10y+24=0 ?
The solutions to the equation y^2-10y+24=0 are y=6,y=4
Find the zeros of y^2-10y+24=0
The zeros of y^2-10y+24=0 are y=6,y=4