What are the solutions to the equation x^2-10x+25=17 ?

The solutions to the equation x^2-10x+25=17 are x=5+sqrt(17),x=5-sqrt(17)

Find the zeros of x^2-10x+25=17

The zeros of x^2-10x+25=17 are x=5+sqrt(17),x=5-sqrt(17)

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x^{2} - 10 x + 25 = 17

x = 5 + 17, x = 5 - 17

Solution steps

x^{2} - 10 x + 25 = 17

Move

17

to the left side

x^{2} - 10 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 8 = 217

x_{1, 2} = \frac{- ( - 10 ) \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 17}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 17}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 17}{2 \cdot 1} : 5 + 17

x = \frac{- ( - 10 ) - 2 17}{2 \cdot 1} : 5 - 17

The solutions to the quadratic equation are:

x = 5 + 17, x = 5 - 17

- \frac{3}{4} y + \frac{9}{8} \leq - \frac{3}{2}

- 3 x^{2} - 5 = - 5

\frac{49}{16} (\frac{4}{35})

- \frac{2}{3} (x + 12) + \frac{2}{3} x = - \frac{5}{4} x + 2

2 x^{2} - 2 x - 40

What are the solutions to the equation x^2-10x+25=17 ?
The solutions to the equation x^2-10x+25=17 are x=5+sqrt(17),x=5-sqrt(17)
Find the zeros of x^2-10x+25=17
The zeros of x^2-10x+25=17 are x=5+sqrt(17),x=5-sqrt(17)