What is (x+3)/8-(x+5)/5 >= 3/10 ?

The solution to (x+3)/8-(x+5)/5 >= 3/10 is x<=-37/3

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(x+3)/8-(x+5)/5 >= 3/10

\frac{x + 3}{8} - \frac{x + 5}{5} \geq \frac{3}{10}

x \leq - \frac{37}{3}

Solution steps

\frac{x + 3}{8} - \frac{x + 5}{5} \geq \frac{3}{10}

Multiply by LCM

5 (x + 3) - 8 (x + 5) \geq 12

Expand

5 (x + 3) - 8 (x + 5) : - 3 x - 25

- 3 x - 25 \geq 12

Move

25

to the right side

- 3 x \geq 37

Multiply both sides by

- 1

3 x \leq - 37

Divide both sides by

3

x \leq - \frac{37}{3}

\frac{1 - ( 1 + 0.055 ) ^{- 20}}{0.055}

16 = x^{2}

2 x + 3 = - 1

x^{2} + 10 x - 39 = 0

p^{2} + 11 pq + 24 q^{2}

What is (x+3)/8-(x+5)/5 >= 3/10 ?
The solution to (x+3)/8-(x+5)/5 >= 3/10 is x<=-37/3