What are the solutions to the equation (y+1)^2=25 ?

The solutions to the equation (y+1)^2=25 are y=4,y=-6

Find the zeros of (y+1)^2=25

The zeros of (y+1)^2=25 are y=4,y=-6

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(y + 1)^{2} = 25

y = 4, y = - 6

Solution steps

(y + 1)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 1 = 25 : y = 4

Solve

y + 1 = - 25 : y = - 6

The solutions to the quadratic equation are:

y = 4, y = - 6

p - 1 = 5 p + 3 p - 8

∣ x + 4 ∣ + 1 = 2

∣ 4 - 2 x ∣ \geq 6

4 x^{2} - 4 x - 80

x^{2} + 2 x - 36 > 12

What are the solutions to the equation (y+1)^2=25 ?
The solutions to the equation (y+1)^2=25 are y=4,y=-6
Find the zeros of (y+1)^2=25
The zeros of (y+1)^2=25 are y=4,y=-6