What are the solutions to the equation 81x^2-36x+4=0 ?

The solutions to the equation 81x^2-36x+4=0 are x= 2/9

Find the zeros of 81x^2-36x+4=0

The zeros of 81x^2-36x+4=0 are x= 2/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

81 x^{2} - 36 x + 4 = 0

x = \frac{2}{9}

Solution steps

81 x^{2} - 36 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 81 \cdot 4}{2 \cdot 81}

(- 36)^{2} - 4 \cdot 81 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 36 ) \pm 0}{2 \cdot 81}

x = \frac{- ( - 36 )}{2 \cdot 81}

\frac{- ( - 36 )}{2 \cdot 81} = \frac{2}{9}

x = \frac{2}{9}

The solution to the quadratic equation is:

x = \frac{2}{9}

(\frac{7}{10})^{2}

x^{2} - 90 x - 16200 = 0

\frac{1}{9} - \frac{1}{12}

610 = \frac{20}{2} [2 a + (20 - 1) 3]

4 (- 4 x - 3) > 36

What are the solutions to the equation 81x^2-36x+4=0 ?
The solutions to the equation 81x^2-36x+4=0 are x= 2/9
Find the zeros of 81x^2-36x+4=0
The zeros of 81x^2-36x+4=0 are x= 2/9