What are the solutions to the equation 3x^2-2x-13=-6 ?

The solutions to the equation 3x^2-2x-13=-6 are x=(1+sqrt(22))/3 ,x=(1-sqrt(22))/3

Find the zeros of 3x^2-2x-13=-6

The zeros of 3x^2-2x-13=-6 are x=(1+sqrt(22))/3 ,x=(1-sqrt(22))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 2 x - 13 = - 6

x = \frac{1 + 22}{3}, x = \frac{1 - 22}{3}

Solution steps

3 x^{2} - 2 x - 13 = - 6

Move

6

to the left side

3 x^{2} - 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 7) = 222

x_{1, 2} = \frac{- ( - 2 ) \pm 2 22}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 22}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 22}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 22}{2 \cdot 3} : \frac{1 + 22}{3}

x = \frac{- ( - 2 ) - 2 22}{2 \cdot 3} : \frac{1 - 22}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 22}{3}, x = \frac{1 - 22}{3}

\frac{3}{4} x - \frac{1}{2} = 4

4 y < 32

∣ x + 6 ∣ = 2 x

8 5^{2}

\frac{1}{2} \cdot 5 \cdot 6

What are the solutions to the equation 3x^2-2x-13=-6 ?
The solutions to the equation 3x^2-2x-13=-6 are x=(1+sqrt(22))/3 ,x=(1-sqrt(22))/3
Find the zeros of 3x^2-2x-13=-6
The zeros of 3x^2-2x-13=-6 are x=(1+sqrt(22))/3 ,x=(1-sqrt(22))/3