What are the solutions to the equation (x-3)(x+4)=0 ?

The solutions to the equation (x-3)(x+4)=0 are x=3,x=-4

Find the zeros of (x-3)(x+4)=0

The zeros of (x-3)(x+4)=0 are x=3,x=-4

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(x - 3) (x + 4) = 0

x = 3, x = - 4

Solution steps

(x - 3) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 4 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

6 - 2

- \frac{31}{2} (\frac{1}{10 0 ^{2}}) + \frac{31}{2}

2 (8 + p) = 22

x^{2} + 14 x = - 40

\frac{6 x y - 4 y}{y}

What are the solutions to the equation (x-3)(x+4)=0 ?
The solutions to the equation (x-3)(x+4)=0 are x=3,x=-4
Find the zeros of (x-3)(x+4)=0
The zeros of (x-3)(x+4)=0 are x=3,x=-4