What are the solutions to the equation -0.2x^2+0.1x+0.04=0 ?

The solutions to the equation -0.2x^2+0.1x+0.04=0 are x=-(-5+sqrt(105))/(20),x=(5+sqrt(105))/(20)

Find the zeros of -0.2x^2+0.1x+0.04=0

The zeros of -0.2x^2+0.1x+0.04=0 are x=-(-5+sqrt(105))/(20),x=(5+sqrt(105))/(20)

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- 0.2 x^{2} + 0.1 x + 0.04 = 0

x = - \frac{- 5 + 105}{20}, x = \frac{5 + 105}{20}

Solution steps

- 0.2 x^{2} + 0.1 x + 0.04 = 0

Multiply both sides by

100

- 20 x^{2} + 10 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 20 ) \cdot 4}{2 ( - 20 )}

1 0^{2} - 4 (- 20) \cdot 4 = 2105

x_{1, 2} = \frac{- 10 \pm 2 105}{2 ( - 20 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 105}{2 ( - 20 )}, x_{2} = \frac{- 10 - 2 105}{2 ( - 20 )}

x = \frac{- 10 + 2 105}{2 ( - 20 )} : - \frac{- 5 + 105}{20}

x = \frac{- 10 - 2 105}{2 ( - 20 )} : \frac{5 + 105}{20}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 105}{20}, x = \frac{5 + 105}{20}

x (x - 6) = 91

7 x - 7 = 17 - 7 x

- 9 - (- 5)

8 (16)^{\frac{7}{4}}

2 7^{\frac{1}{2}}

What are the solutions to the equation -0.2x^2+0.1x+0.04=0 ?
The solutions to the equation -0.2x^2+0.1x+0.04=0 are x=-(-5+sqrt(105))/(20),x=(5+sqrt(105))/(20)
Find the zeros of -0.2x^2+0.1x+0.04=0
The zeros of -0.2x^2+0.1x+0.04=0 are x=-(-5+sqrt(105))/(20),x=(5+sqrt(105))/(20)