What are the solutions to the equation 4x^2=25 ?

The solutions to the equation 4x^2=25 are x= 5/2 ,x=-5/2

Find the zeros of 4x^2=25

The zeros of 4x^2=25 are x= 5/2 ,x=-5/2

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4 x^{2} = 25

x = \frac{5}{2}, x = - \frac{5}{2}

Solution steps

4 x^{2} = 25

Divide both sides by

4

x^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{4}, x = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

- 52 \leq 8

16 x^{2} + 40 x = - 25

(x - 2) (x - 5) (x - 6) \leq 0

- 1.6 t + 16 = 0

\frac{\frac{15}{6}}{- \frac{7}{2}}

What are the solutions to the equation 4x^2=25 ?
The solutions to the equation 4x^2=25 are x= 5/2 ,x=-5/2
Find the zeros of 4x^2=25
The zeros of 4x^2=25 are x= 5/2 ,x=-5/2