What are the solutions to the equation v^2+6v+9=0 ?

The solutions to the equation v^2+6v+9=0 are v=-3

Find the zeros of v^2+6v+9=0

The zeros of v^2+6v+9=0 are v=-3

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v^{2} + 6 v + 9 = 0

v = - 3

Solution steps

v^{2} + 6 v + 9 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

v_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

v = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

v = - 3

The solution to the quadratic equation is:

v = - 3

2 x (x + 8) = (x - 5) (x + 8)

3 x^{2} - 10 x + 5 = 0

3 - \frac{5}{2}

3 (4 x + 1) - 4 x + 3 = - 18

\frac{600}{4}

What are the solutions to the equation v^2+6v+9=0 ?
The solutions to the equation v^2+6v+9=0 are v=-3
Find the zeros of v^2+6v+9=0
The zeros of v^2+6v+9=0 are v=-3