What are the solutions to the equation g^2-10g=-19 ?

The solutions to the equation g^2-10g=-19 are g=5+sqrt(6),g=5-sqrt(6)

Find the zeros of g^2-10g=-19

The zeros of g^2-10g=-19 are g=5+sqrt(6),g=5-sqrt(6)

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g^{2} - 10 g = - 19

g = 5 + 6, g = 5 - 6

Solution steps

g^{2} - 10 g = - 19

Move

19

to the left side

g^{2} - 10 g + 19 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 19 = 26

g_{1, 2} = \frac{- ( - 10 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

g_{1} = \frac{- ( - 10 ) + 2 6}{2 \cdot 1}, g_{2} = \frac{- ( - 10 ) - 2 6}{2 \cdot 1}

g = \frac{- ( - 10 ) + 2 6}{2 \cdot 1} : 5 + 6

g = \frac{- ( - 10 ) - 2 6}{2 \cdot 1} : 5 - 6

The solutions to the quadratic equation are:

g = 5 + 6, g = 5 - 6

2 (4 x - 3) - 8 = 4 + 2 x

y^{2} - 8 y + 12 = 0

- x \leq 5

3 x^{2} + 2 x + 4 > 0

\frac{3}{x - 3} \geq \frac{2}{x + 2}

What are the solutions to the equation g^2-10g=-19 ?
The solutions to the equation g^2-10g=-19 are g=5+sqrt(6),g=5-sqrt(6)
Find the zeros of g^2-10g=-19
The zeros of g^2-10g=-19 are g=5+sqrt(6),g=5-sqrt(6)