What are the solutions to the equation k(k-4)=0 ?

The solutions to the equation k(k-4)=0 are k=0,k=4

Find the zeros of k(k-4)=0

The zeros of k(k-4)=0 are k=0,k=4

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k (k - 4) = 0

k = 0, k = 4

Solution steps

k (k - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

k = 0 or k - 4 = 0

Solve

k - 4 = 0 : k = 4

The solutions to the quadratic equation are:

k = 0, k = 4

x^{2} + 12 x + 35

2 x^{2} - 1 x - 1

4 + 7 y = 3 + 8 y

\frac{2 c}{15} = 8.8

\frac{52 !}{( 52 - 4 ) ! 4 !}

What are the solutions to the equation k(k-4)=0 ?
The solutions to the equation k(k-4)=0 are k=0,k=4
Find the zeros of k(k-4)=0
The zeros of k(k-4)=0 are k=0,k=4