What is (5x-3)/6+(x-5}{18}<\frac{x+1)/3 ?

The solution to (5x-3)/6+(x-5}{18}<\frac{x+1)/3 is x<2

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(5x-3)/6+(x-5}{18}<\frac{x+1)/3

\frac{5 x - 3}{6} + \frac{x - 5}{18} < \frac{x + 1}{3}

x < 2

Interval Notation

(- \infty, 2)

Solution steps

\frac{5 x - 3}{6} + \frac{x - 5}{18} < \frac{x + 1}{3}

Multiply by LCM

3 (5 x - 3) + x - 5 < 6 (x + 1)

Expand

3 (5 x - 3) + x - 5 : 16 x - 14

Expand

6 (x + 1) : 6 x + 6

16 x - 14 < 6 x + 6

Move

14

to the right side

16 x < 6 x + 20

Move

6 x

to the left side

10 x < 20

Divide both sides by

10

x < 2

3 w - 15 w - 16 = - 52

3 x \geq 12

- 2 x^{2} + x - 5 = 0

(\frac{- 3 uv}{w ^{5}})^{2}

5 n^{2} + 24 n - 5

What is (5x-3)/6+(x-5}{18}<\frac{x+1)/3 ?
The solution to (5x-3)/6+(x-5}{18}<\frac{x+1)/3 is x<2