What are the solutions to the equation 2w^2+5w-63=0 ?

The solutions to the equation 2w^2+5w-63=0 are w= 9/2 ,w=-7

Find the zeros of 2w^2+5w-63=0

The zeros of 2w^2+5w-63=0 are w= 9/2 ,w=-7

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2 w^{2} + 5 w - 63 = 0

w = \frac{9}{2}, w = - 7

Decimal Notation

w = 4.5, w = - 7

Solution steps

2 w^{2} + 5 w - 63 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 63 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 63) = 23

w_{1, 2} = \frac{- 5 \pm 23}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- 5 + 23}{2 \cdot 2}, w_{2} = \frac{- 5 - 23}{2 \cdot 2}

w = \frac{- 5 + 23}{2 \cdot 2} : \frac{9}{2}

w = \frac{- 5 - 23}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

w = \frac{9}{2}, w = - 7

x, f (a + h) = 7 x^{2} + 6

5 x^{4} + 10 x^{3} + 15 x^{2}

- 4 - 2 i

6 x + 24

\frac{14 !}{10 ! ( 14 - 10 ) !}

What are the solutions to the equation 2w^2+5w-63=0 ?
The solutions to the equation 2w^2+5w-63=0 are w= 9/2 ,w=-7
Find the zeros of 2w^2+5w-63=0
The zeros of 2w^2+5w-63=0 are w= 9/2 ,w=-7