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Frequently Asked Questions (FAQ)
What are the solutions to the equation x^2+4x-16=0 ?
- The solutions to the equation x^2+4x-16=0 are x=2(sqrt(5)-1),x=-2(1+sqrt(5))
Find the zeros of x^2+4x-16=0
- The zeros of x^2+4x-16=0 are x=2(sqrt(5)-1),x=-2(1+sqrt(5))