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Frequently Asked Questions (FAQ)
What are the solutions to the equation 12-4x+24x^2=0 ?
- The solutions to the equation 12-4x+24x^2=0 are x= 1/12+i(sqrt(71))/(12),x= 1/12-i(sqrt(71))/(12)
Find the zeros of 12-4x+24x^2=0
- The zeros of 12-4x+24x^2=0 are x= 1/12+i(sqrt(71))/(12),x= 1/12-i(sqrt(71))/(12)