What is the tangent of f(x)=(6x)/(2+x^2),(2,2) ?

The tangent of f(x)=(6x)/(2+x^2),(2,2) is y=-1/3 x+8/3

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tangent of f(x)=(6x)/(2+x^2),(2,2)

tangent of

f (x) = \frac{6 x}{2 + x ^{2}}, (2, 2)

y = - \frac{1}{3} x + \frac{8}{3}

Solution steps

Find the slope of

f (x) = \frac{6 x}{2 + x ^{2}} : \frac{df ( x )}{d x} = \frac{6 ( 2 - x ^{2} )}{( 2 + x ^{2} ) ^{2}}

Compute the slope of

f (x) = \frac{6 x}{2 + x ^{2}}

(2, 2) : m = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(2, 2) : y = - \frac{1}{3} x + \frac{8}{3}

y = - \frac{1}{3} x + \frac{8}{3}

\int (3 x + 2) d x

y = 19 cos (\frac{x}{b} - 2.5) + 19

\frac{\partial}{\partial x} (sin^{2} (2 x + 3 y))

\int_{0}^{1} x^{2} (x^{3} - 2)^{3} d x

\frac{\partial}{\partial x} (\frac{t}{x})

What is the tangent of f(x)=(6x)/(2+x^2),(2,2) ?
The tangent of f(x)=(6x)/(2+x^2),(2,2) is y=-1/3 x+8/3