What is the solution for y^'=-y+sin(x)+cos(x) ?

The solution for y^'=-y+sin(x)+cos(x) is y=sin(x)+(c_{1})/(e^x)

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y^'=-y+sin(x)+cos(x)

y^{^{'}} = - y + sin (x) + cos (x)

y = sin (x) + \frac{c _{1}}{e ^{x}}

Solution steps

y^{'} (x) = - y + sin (x) + cos (x)

Solve linear ODE:

y = sin (x) + \frac{c _{1}}{e ^{x}}

y = sin (x) + \frac{c _{1}}{e ^{x}}

f (x) = 3 x + 2 z + 4 x z

\int_{1}^{7} \frac{ln ( x )}{x} d x

x \to 1 lim (3 x^{2})

\frac{\partial}{\partial x} (y^{5 x})

\frac{d}{d x} (4 - e^{x})

What is the solution for y^'=-y+sin(x)+cos(x) ?
The solution for y^'=-y+sin(x)+cos(x) is y=sin(x)+(c_{1})/(e^x)