What is the derivative of \sqrt[3]{tan^2(x}) ?

The derivative of \sqrt[3]{tan^2(x}) is (2sec^2(x))/(3tan^{1/3)(x)}

What is the first derivative of \sqrt[3]{tan^2(x}) ?

The first derivative of \sqrt[3]{tan^2(x}) is (2sec^2(x))/(3tan^{1/3)(x)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{2 sec ^{2} ( x )}{3 tan ^{\frac{1}{3}} ( x )}

Solution steps

Apply the chain rule:

\frac{1}{3 ( tan ^{2} ( x ) ) ^{\frac{2}{3}}} \frac{d}{d x} (tan^{2} (x))

= \frac{1}{3 ( tan ^{2} ( x ) ) ^{\frac{2}{3}}} \frac{d}{d x} (tan^{2} (x))

\frac{d}{d x} (tan^{2} (x)) = 2 tan (x) sec^{2} (x)

= \frac{1}{3 ( tan ^{2} ( x ) ) ^{\frac{2}{3}}} \cdot 2 tan (x) sec^{2} (x)

Simplify

\frac{1}{3 ( tan ^{2} ( x ) ) ^{\frac{2}{3}}} \cdot 2 tan (x) sec^{2} (x) : \frac{2 sec ^{2} ( x )}{3 tan ^{\frac{1}{3}} ( x )}

= \frac{2 sec ^{2} ( x )}{3 tan ^{\frac{1}{3}} ( x )}

\frac{d}{d x} (lo g_{n} (x))

t^{2} \frac{d y}{d t} + y^{2} = t y

\int x (1 - 2 x) d x

\frac{d}{d x} (\frac{3 x ^{2} + 2 x}{x})

\frac{d}{d x} (cot (x) csc (x))

What is the derivative of \sqrt[3]{tan^2(x}) ?
The derivative of \sqrt[3]{tan^2(x}) is (2sec^2(x))/(3tan^{1/3)(x)}
What is the first derivative of \sqrt[3]{tan^2(x}) ?
The first derivative of \sqrt[3]{tan^2(x}) is (2sec^2(x))/(3tan^{1/3)(x)}