What is taylor-4x^3+3x^2-6x+10 ?

The answer to taylor-4x^3+3x^2-6x+10 is 10-6x+3x^2-4x^3

Popular >

taylor-4x^3+3x^2-6x+10

taylor

- 4 x^{3} + 3 x^{2} - 6 x + 10

10 - 6 x + 3 x^{2} - 4 x^{3}

Solution steps

Apply the Taylor Formula

= 10 + \frac{\frac{d}{d x} ( - 4 x ^{3} + 3 x ^{2} - 6 x + 10 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( - 4 x ^{3} + 3 x ^{2} - 6 x + 10 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( - 4 x ^{3} + 3 x ^{2} - 6 x + 10 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 10 + \frac{- 6}{1 !} x + \frac{6}{2 !} x^{2} + \frac{- 24}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Refine

= 10 - 6 x + 3 x^{2} - 4 x^{3}

y = x^{3} - 14 x^{2} + 32 x + 4

s \to 0 lim (\frac{- 2 s}{s - 3})

y = - x^{2} + 4, y = 1 - x

\int_{1}^{6} \frac{x ^{2} - 1}{x} d x

y^{^{''}} - 2 y^{^{'}} + 2 y = 2 x - 2, y (0) = 0, y (π) = π

What is taylor-4x^3+3x^2-6x+10 ?
The answer to taylor-4x^3+3x^2-6x+10 is 10-6x+3x^2-4x^3