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Popular >

derivative of s(t)= 1/(t+1)

Solution

derivative of

s (t) = \frac{1}{t + 1}

Solution

- \frac{1}{( t + 1 ) ^{2}}

Solution steps

\frac{d}{d t} (\frac{1}{t + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} ((t + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( t + 1 ) ^{2}} \frac{d}{d t} (t + 1)

= - \frac{1}{( t + 1 ) ^{2}} \frac{d}{d t} (t + 1)

\frac{d}{d t} (t + 1) = 1

= - \frac{1}{( t + 1 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( t + 1 ) ^{2}}

Popular Examples

derivative of cos(e^{-x^2})derivative of

cos (e^{- x^{2}})

xy^'+y=x^2ln(x)

x y^{^{'}} + y = x^{2} ln (x)

sum from n=1 to infinity of (0.5)^{-n}

n = 1 \sum \infty (0.5)^{- n}

integral of 4xcos(3x)

\int 4 x cos (3 x) d x

(\partial)/(\partial u)(sqrt(u^2+v^2))

\frac{\partial}{\partial u} (u^{2} + v^{2})

Frequently Asked Questions (FAQ)

What is the derivative of s(t)= 1/(t+1) ?
The derivative of s(t)= 1/(t+1) is -1/((t+1)^2)
What is the first derivative of s(t)= 1/(t+1) ?
The first derivative of s(t)= 1/(t+1) is -1/((t+1)^2)