What is the derivative of e^{x^2+9x+7} ?

The derivative of e^{x^2+9x+7} is e^{x^2+9x+7}(2x+9)

What is the first derivative of e^{x^2+9x+7} ?

The first derivative of e^{x^2+9x+7} is e^{x^2+9x+7}(2x+9)

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derivative of

e^{x^{2} + 9 x + 7}

e^{x^{2} + 9 x + 7} (2 x + 9)

Solution steps

\frac{d}{d x} (e^{x^{2} + 9 x + 7})

Apply the chain rule:

e^{x^{2} + 9 x + 7} \frac{d}{d x} (x^{2} + 9 x + 7)

= e^{x^{2} + 9 x + 7} \frac{d}{d x} (x^{2} + 9 x + 7)

\frac{d}{d x} (x^{2} + 9 x + 7) = 2 x + 9

= e^{x^{2} + 9 x + 7} (2 x + 9)

n = 2 \sum \infty 2 n ln (n)

\frac{d}{d x} (\frac{x - 7}{x + 7})

\int 9 x^{\frac{2}{3}} d x

x \to - \infty lim (3 - 2^{x})

ln (\frac{x}{x ^{2} + c})

What is the derivative of e^{x^2+9x+7} ?
The derivative of e^{x^2+9x+7} is e^{x^2+9x+7}(2x+9)
What is the first derivative of e^{x^2+9x+7} ?
The first derivative of e^{x^2+9x+7} is e^{x^2+9x+7}(2x+9)