What is (\partial)/(\partial x)(xy-ln(z)) ?

The answer to (\partial)/(\partial x)(xy-ln(z)) is y

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(\partial)/(\partial x)(xy-ln(z))

\frac{\partial}{\partial x} (x y - ln (z))

y

Solution steps

\frac{\partial}{\partial x} (x y - ln (z))

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (ln (z))

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (ln (z)) = 0

= y - 0

Simplify

= y

\int e^{x + y} d y

\frac{\partial}{\partial s} (\frac{s ^{2} + 4}{t - 3})

x \to 0 - lim (\frac{2 x}{∣ x ∣})

t y^{^{''}} - y^{^{'}} = t^{2} + t, y (1) = 1, y^{^{'}} (1) = 5

(3, - 7), (10, - 4)

What is (\partial)/(\partial x)(xy-ln(z)) ?
The answer to (\partial)/(\partial x)(xy-ln(z)) is y