What is area x=-2,x=1,y=11x,y=x^2-12 ?

The answer to area x=-2,x=1,y=11x,y=x^2-12 is 181/6

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area x=-2,x=1,y=11x,y=x^2-12

area

x = - 2, x = 1, y = 11 x, y = x^{2} - 12

\frac{181}{6}

Decimal Notation

30.16666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{1} 11 x - (x^{2} - 12) d x

Solve

\int_{- 2}^{1} 11 x - (x^{2} - 12) d x : \frac{181}{6}

The area is:

= \frac{181}{6}

\frac{d}{d x} (400 - 5 x)

\int v (u + v^{2})^{4} d u

\int sin (θ) d θ

\frac{d}{d x} (6 x + 7 x)

\frac{\partial}{\partial x} (- 2 x^{2} + y^{2})

What is area x=-2,x=1,y=11x,y=x^2-12 ?
The answer to area x=-2,x=1,y=11x,y=x^2-12 is 181/6