What is the limit as h approaches 0 of ((1+h)^3-1)/h ?

The limit as h approaches 0 of ((1+h)^3-1)/h is 3

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limit as h approaches 0 of ((1+h)^3-1)/h

h \to 0 lim (\frac{( 1 + h ) ^{3} - 1}{h})

3

Solution steps

h \to 0 lim (\frac{( 1 + h ) ^{3} - 1}{h})

Simplify

\frac{( 1 + h ) ^{3} - 1}{h} : h^{2} + 3 h + 3

= h \to 0 lim (h^{2} + 3 h + 3)

Plug in the value

h = 0

= 0^{2} + 3 \cdot 0 + 3

Simplify

= 3

\int \frac{1}{1 + cos ( x )} d x

\frac{d}{d x} (5 x 64 - x^{2})

\frac{x}{1 - x ^{2}}

f (x) = 8 x

\frac{d}{d x} (lo g_{3} (x e^{x}))

What is the limit as h approaches 0 of ((1+h)^3-1)/h ?
The limit as h approaches 0 of ((1+h)^3-1)/h is 3